What's the best travel credit card with no annual fee?

The best travel credit card with no annual fee is the Capital One VentureOne card because it offers an initial bonus of 20,000 miles for spending $1,000 in the first 3 months. It also rewards cardholders with at least 1.25 miles per $1 spent on all purchases. VentureOne has a $0 foreign transaction fee in addition to its $0 annual fee.

If you aren’t planning to go anywhere too adventurous, consider the Discover it Miles card. Discover’s not accepted in as many international locations as Visa or Mastercard, but its US acceptance is pretty good. The Discover Miles card also has good rewards. It offers 1.5 miles per $1 spent on all purchases, doubled year one.

I like the Discover it Miles. You get 1.5 miles for every dollar spent on purchases. There's no APR for the first 14 months, and they match all the miles you've earned at the end of the first year.

Fortunately, your options are not limited. WalletHub’s editors have a great selection of best travel credit cards at: https://wallethub.com/best-travel-credit-cards/. And some of the best don’t charge an annual fee during the first year of account activity – examples include the Chase Sapphire Preferred®, the Starwood Preferred Guest® from American Express, PenFed Platinum Rewards Visa Signature®, and the Citi® Double Cash. That being said, please note that travel insurance and travel accident insurance are driven by the card networks – Visa, Mastercard, and AmEx. You can identify the cards with the best coverage here: https://wallethub.com/edu/credit-card-travel-insurance/25820/. Hope this helps.

Travel Rewards from BoA is definitely one of the best ones. Good signup bonus, no foreign transaction fees, and an intro APR period of 12 months.

Bank of America Travel Rewards is a good pick imo. 1.5 points on every dollar spent and a signup bonus: 20,000 online bonus points if you make at least $1,000 in purchases in the first 90 days of account opening - that can be a $200 statement credit toward travel purchases.